力扣-链表-19 删除链表倒数第N个节点

思路

链表题目中操作链表的需要找到要操作节点的上一个节点，所以cur是当前想要操作的节点上一个节点

代码

class Solution {
public:ListNode* removeNthFromEnd(ListNode* head, int n) {ListNode* dummy_head = new ListNode();dummy_head->next = head;int size = 0;while(head != nullptr){head = head->next;size++;}ListNode* cur = dummy_head;while(size - n){cur = cur->next;n++;}cur->next = cur->next->next;return dummy_head->next;}
};