力扣1089复写0

1089. 复写零 - 力扣（LeetCode）

我们的思路是利用类似双指针的方式去解答，来看下代码

class Solution {
public:void duplicateZeros(vector<int>& arr){int cur = 0, dest = -1, n = arr.size();while (cur < n){if (arr[cur])dest++;elsedest += 2;if (dest >= n - 1){break;}cur++;}if (dest == n){arr[n - 1] = 0;cur--;dest -=2;}while (dest >= 0){if(arr[cur]){arr[dest--] = arr[cur--];}else{arr[dest--] = 0;arr[dest--] = 0;cur--;}}}
};