number的++和--运算 C#

number=10     请计算num = number++ + --number - ++number

• number++就是先对number运算，然后再给number赋值
• --number 先给number赋值，再拿来运算

using System;class Program
{static void Main(string[] args){int number = 10;int a, b, c, number1, number2;a = number++;number1 = number;Console.WriteLine("第一步运算number++给num赋值{0}", a);Console.WriteLine("number这时候等于{0}", number1);Console.WriteLine();number = 10;b = number++ + --number;number2 = number;Console.WriteLine("第二步运算number++ + -- number给num赋值{0}", b);Console.WriteLine("number这时候等于{0}", number2);Console.WriteLine();number = 10;c = number++ + --number - ++number;Console.WriteLine("完整的，number=10, 计算num = number++ + --number - ++number = {0}", c);Console.WriteLine("num这时候等于{0}，相当于10+10-11", c);Console.ReadLine();}
}

输出结果：

第一步运算number++给num赋值10
number这时候等于11第二步运算number++ + -- number给num赋值20
number这时候等于10完整的，number=10, 计算num = number++ + --number - ++number = 9
num这时候等于9，相当于10+10-11