[保研/考研机试] KY109 Zero-complexity Transposition 上海交通大学复试上机题 C++实现

描述：

You are given a sequence of integer numbers. Zero-complexity transposition of the sequence is the reverse of this sequence. Your task is to write a program that prints zero-complexity transposition of the given sequence.

输入描述：

For each case, the first line of the input file contains one integer n-length of the sequence (0 ＜ n ≤ 10 000). The second line contains n integers numbers-a1, a2, …, an (-1 000 000 000 000 000 ≤ ai ≤ 1 000 000 000 000 000).

输出描述：

For each case, on the first line of the output file print the sequence in the reverse order.

示例1：

输入：
5
-3 4 6 -8 9输出：
9 -8 6 4 -3

源代码：

#include<iostream>
#include<stack>
using namespace std;//例题5.4 Zero-complexity Transposition
int main()
{int n;cin >> n;stack<int> myStack;for (int i = 0; i < n; i++) {int temp = 0;cin >> temp;myStack.push(temp);}cout << myStack.top();myStack.pop();while (!myStack.empty()) {cout << " " << myStack.top();myStack.pop();}cout << endl;return 0;
}
// 64 位输出请用 printf("%lld")

提交结果：