C语言：求和1+1/2-1/3+1/4-1/5+……-1/99+1/100

#include<stdio.h>
int main()
{int i = 0;double sum = 0.0;int flag = 1;for (i = 1;i <= 100;i++){sum += 1.0 / i * flag;flag = -flag;}printf("sum=%lf\n", sum);return 0;
}