【快慢指针】26.删除有序数组中的重复项

题目

法1：快慢指针

基础解法，必须掌握！！！

class Solution {public int removeDuplicates(int[] nums) {if (nums.length < 2) {return nums.length;}int slow = 0, fast = 1;while (fast < nums.length) {if (nums[fast] > nums[slow]) {nums[++slow] = nums[fast++];} else {fast++;}}return slow + 1;}
}