leetcode打卡#day45 携带研究材料（第七期模拟笔试）、518. 零钱兑换 II、377. 组合总和 Ⅳ、爬楼梯（第八期模拟笔试）

携带研究材料（第七期模拟笔试）

#include<iostream>
#include<algorithm>
#include<vector>using namespace std;int main() {int N, V;cin >> N >> V;vector<int> weights(N+1);vector<int> values(V+1);int w, v;for (int i = 0; i < N; i++) {cin >> w >> v;weights.push_back(w);values.push_back(v);}vector<int> pd(N+1, 0);//先遍历背包容量for (int i = 0; i < V; i++) {//再遍历物品for (int j = 0; j < N; j ++) {if (i - weights[j] >= 0) pd[i] = max(pd[i], pd[i-weights[j]] + values[j]);}}cout << pd[V];return 0;}

518. 零钱兑换 II

//不包含顺序
class Solution {
public:int change(int amount, vector<int>& coins) {int n = coins.size();//凑成amount的组合数vector<int> pd(amount + 1, 0);pd[0] = 1;//先遍历物品for (int i = 0; i < n; i++) {//再遍历容量for (int j = coins[i]; j <= amount; j++) {pd[j] += pd[j - coins[i]];}}return pd[amount];}
};

377. 组合总和 Ⅳ

//包含顺序
class Solution {
public:int combinationSum4(vector<int>& nums, int target) {//目标为i的组合数vector<int> dp(target+1, 0);int n = nums.size();dp[0] = 1;//先容量再物体 -- 排序数for (int i = 0; i <= target; i++) {//遍历背包for (int j = 0; j < n; j++) {if (i - nums[j] >= 0 && dp[i] < INT_MAX - dp[i - nums[j]]) dp[i] += dp[i - nums[j]];}}return dp[target];}
};

爬楼梯（第八期模拟笔试）

#include<iostream>
#include<algorithm>
#include<vector>using namespace std;int main() {int m, n;cin >> n >> m;vector<int> dp(n+1, 0);dp[0] = 1;//包含顺序，排序：先容量再物品for (int i = 0; i <= n; i++) {for (int j = 1; j <= m; j++) {if (i - j >= 0) dp[i] += dp[i - j];}}cout << dp[n] << endl;return 0;
}