Python | Leetcode Python题解之第539题最小时间差

题目：

题解：

def getMinutes(t: str) -> int:return ((ord(t[0]) - ord('0')) * 10 + ord(t[1]) - ord('0')) * 60 + (ord(t[3]) - ord('0')) * 10 + ord(t[4]) - ord('0')class Solution:def findMinDifference(self, timePoints: List[str]) -> int:n = len(timePoints)if n > 1440:return 0timePoints.sort()ans = float('inf')t0Minutes = getMinutes(timePoints[0])preMinutes = t0Minutesfor i in range(1, n):minutes = getMinutes(timePoints[i])ans = min(ans, minutes - preMinutes)  # 相邻时间的时间差preMinutes = minutesans = min(ans, t0Minutes + 1440 - preMinutes)  # 首尾时间的时间差return ans