某公司前端笔试题（12.30）

1、对象数组去重：

数组去重：

    const a=[{a:1,b:2},{a:2},{a:2},{a:1,c:3},{b:2,a:1}]

结果：[{a:1,b:2},{a:2},{a:1,c:3}]

// 判断两个对象的属性值是否一致
const a = [{ a: 1, b: 2 }, { a: 2 }, { a: 2 }, { a: 1, c: 3 }, { b: 2, a: 1 }]
const isSameObject = (a, b) => {if (Object.keys(a).length !== Object.keys(b).length) return false;for (const key in a) {if (Object.hasOwnProperty.call(a, key)) {if (a[key] !== b[key]) return false}}return true;
}
const uniqueFn = (tempArr) => {const res = tempArr.slice(0)for (let i = 0; i < tempArr.length; i++) {for (let j = i + 1; j < tempArr.length; j++) {if (isSameObject(tempArr[i], tempArr[j])) {console.log(i, j);res.splice(i, 1)};};};return res;
}
console.log(uniqueFn(a));

2、事件循环相关 

setTimeout(function() {console.log('setTimeout1');    // 8  setTimeout1new Promise(function(resolve) {console.log('promise0');  // 9  promise0resolve()}).then(function() {console.log('settimeout promise resolveed');   // 10  settimeout promise resolveed})
});setTimeout(function() {console.log('setTimeout2');  // 11  setTimeout2
});const P = new Promise(function(resolve) {console.log('promise');    // 1  promisefor (var i = 0; i < 10000; i++) {if(i === 10) {console.log('for'); // 2  for}if (i === 9999) {resolve('resolve'); }}
}).then(function(val) {console.log('resolve1');    // 5  resolve1
}).then(function(val) {console.log('resolve2');     // 6  resolve2
});new Promise(function(resolve) {console.log('promise2');     // 3  promise2resolve('resolve');
}).then(function(val) {console.log('resolve3');   //  7  resolve3
})
console.log('console');       // 4  console

3、扁平化数组

实现一个flat函数，把嵌套的数组打平，flat([[1,2,[3,[4,[5]]]]]),返回[1,2,3,4,5]

const flat = (nums) => {const res = nums.reduce((pre, cur) => {if (Array.isArray(cur)) {return [...pre, ...flat(cur)]} else {pre.push(cur)}return pre}, [])return res;
}
console.log(flat([[1, 2, [3, [4, [5]]]]])); // [ 1, 2, 3, 4, 5 ]