力扣算法题：将数字变为0的操作次数--多语言实现

无意间看到，力扣存算法代码居然还得升级vip。。。好吧，我自己存吧

golang：

func numberOfSteps(num int) int {steps := 0for num > 0 {if num%2 == 0 {num /= 2} else {num -= 1}steps++}return steps
}

javascript:

/*** @param {number} num* @return {number}*/
var numberOfSteps = function(num) {let step = 0;while(num > 0){if (num % 2 === 0) {num /= 2} else {num -= 1}step++}return step     
};

python:

class Solution(object):def numberOfSteps(self, num):""":type num: int:rtype: int"""step = 0while num > 0:if num % 2 == 0:num //= 2else:num -= 1step += 1return step