python函数练习

1、编写函数，传入N，求1+2+3+…N的和

def s_sum(num):i = 1sum1 = 0while i <= num:sum1 += ii += 1return sum1num = int(input('请输入一个整数：'))
print('和为:',s_sum(num))

2、编写一个函数，定义一个列表，求列表中的最大值

def n_max(nums):max_num = 0for x in nums:if max_num < x:max_num = xreturn max_numnums = [12,23,12,34,55,65,43,23,78,1,89]
print('最大值为:',n_max(nums))

3、编写一个函数，实现摇骰子的功能，打印N个骰子的点数和

from random import randint
def s_sum(n):b = 0while n > 0:a = randint(1, 6)b += an -= 1return bn = int(input('请输入骰子个数：'))
print(s_sum(n))

4、编写一个函数，提取指定字符串中所有的字母，然后拼接在一起产生一个新的字符串

例如: 传入'12a&bc12d-+'   -->  'abcd'  
def zi_mu(str1):str2 = ''for x in str1:if 'a' <= x <= 'z' or 'A' <= x <= 'Z':str2 += xreturn str2   str1 = '12a&bc12d-+'
print(zi_mu(str1))

5、写一个函数，求列表的平均值

def n_avg(nums):sum_num = 0for x in nums:sum_num += xreturn sum_num / len(nums)   nums = [12,23,12,34,55,65,43,23,78,1,89]
print('平均值为:',n_avg(nums))

6、写一个函数，求10的阶乘

def factorial(n):x = 1while n > 0:x *= nn -= 1return xprint(factorial(10))

7、写一个函数实现自己in操作，判断指定序列中，指定的元素是否存在

例如: 序列: (12, 90, 'abc')   元素: '90'     结果: False序列: [12, 90, 'abc']   元素: 90     结果: True     
def str_in(s1,s2):flag = Falsefor x in s1:if x == s2:flag = Truebreakreturn flagparam1 = (12, 90, 'abc')
str1 = '90'
print(str_in(param1,str1))

8、写三个函数，分别实现求两个列表的交集、并集、差集的功能

def jiao_ji(list1, list2):jiao_ji = []for x in list1:if x in list2:jiao_ji.append(x)return jiao_jidef bing_ji(list1, list2):bing_ji = []for x in list1:bing_ji.append(x)for y in list2:if y not in bing_ji:bing_ji.append(y)return bing_jidef cha_ji(list1, list2):cha_ji = []for x in list1:if x not in list2:cha_ji.append(x)return cha_jilist1 = [2, 4, 6, 8, 10, 12, 14, 16]
list2 = [2, 4, 6, 8]
print(jiao_ji(list1, list2))
print(bing_ji(list1, list2))
print(cha_ji(list1, list2))

9、输入一个数，判断这个数是否是质数（要求使用函数 + for循环）

def zhishu(num):for i in range(2, num//2+1):if num % i == 0:return (f"{num}不是质数")return (f"{num}是质数")num = int(input('请输入一个数：'))
print(zhishu(num))

10、编写一个函数，输出50~150之间的质数？

def zhishu(num):for i in range(2, num//2+1):if num % i == 0:return Falsereturn Truefor i in range(50, 151):if zhishu(i):print(f"{i}是质数")

11、编写一个函数，输出100~1000之间的水仙花数？

def num1():for num in range(100, 1000):i = num // 100j = num // 10 % 10k = num % 10if num == i ** 3 + j ** 3 + k ** 3:print(f"输出的水仙花数为：{num}")num1()

12、编程求出满足以下条件的三位数:它除以11所得的商等于它各位数字之和

def nums():for num in range(100, 1000):i = (num % 100) % 10j = (num % 100)//10k = num//100sums = i+j+kif sums == num/11:print("满足条件的三位数为：%s" % num)breaknums()

13、编写一个函数，求1~100之间不能被3整除的数之和

def sums():sum = 0for num in range(1, 101):if num % 3 != 0:sum += numprint(f"1~100之间不能被3整除的数之和为：{sum}")sums()