C语言 | Leetcode C语言题解之第328题奇偶链表

题目：

题解：

struct ListNode* oddEvenList(struct ListNode* head) {if (head == NULL) {return head;}struct ListNode* evenHead = head->next;struct ListNode* odd = head;struct ListNode* even = evenHead;while (even != NULL && even->next != NULL) {odd->next = even->next;odd = odd->next;even->next = odd->next;even = even->next;}odd->next = evenHead;return head;
}