【宽搜】2. leetcode 102 二叉树的层序遍历

题目描述

题目链接：二叉树的层序遍历

根据上一篇文章的模板可以直接写代码，需要改变的就是将N叉树的child改为二叉树的left和right。

代码

class Solution {
public:vector<vector<int>> levelOrder(TreeNode* root) {vector<vector<int>> res;queue<TreeNode*> q;if (root == nullptr)return res;q.push(root);while(q.size()){vector<int> tmp;int sz = q.size();for (int i = 0; i < sz; ++ i){TreeNode* t = q.front();q.pop();tmp.push_back(t->val);if (t->left)q.push(t->left);if (t->right)q.push(t->right);}res.push_back(tmp);}return res;}
};