C语言最简单的扫雷实现（解析加原码）

头文件

#define ROW 9
#define COL 9
#define ROWS ROW+2
#define COLS COL+2
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#define numlei 10

do while可以循环玩
两个板子，内板子放0，外板子放*
set函数初始化两个板子
lei函数，x,y随机两数,把内板子某些0改为1
print函数打印内或外板子
board返回周围8个格子雷的个数

#include "game.h"
void set(char arr[ROWS][COLS], int row, int col,char set)
{for (int i = 0;i < ROWS;i++){for (int j = 0;j < COLS;j++){arr[i][j] = set;}}
}
void lei(char arr[ROWS][COLS], int row, int col)
{int count = numlei;while (count){int x = rand() % 9 + 1;int y = rand() % 9 + 1;if (arr[x][y]=='0'){arr[x][y] = '1';count--;}}
}
void print(char arr[ROWS][COLS], int row, int col)
{for (int i=0;i<=row;i++){printf("%d ",i);}printf("\n");for (int i = 1;i <= row;i++){printf("%d ", i);for (int j = 1;j <= col;j++){   printf("%c ", arr[i][j]);}printf("\n");}
}
int board(char mine[ROWS][COLS], int x, int y)
{return  (mine[x - 1][y] + mine[x - 1][y - 1] + mine[x][y - 1] + mine[x + 1][y-1] + mine[x + 1][y] + mine[x + 1][y + 1] + mine[x][y + 1] + mine[x - 1][y + 1]-8*'0');}void game()
{printf("********************\n");printf("**** 1.游戏开始 ****\n");printf("**** 0.退出游戏 ****\n");printf("********************\n");int input;char show[ROWS][COLS];char inside[ROWS][COLS];do{scanf("%d", &input);switch (input){case 1:printf("游戏开始\n");set(show, ROW, COL, '*');print(show, ROW, COL);set(inside, ROW, COL, '0');lei(inside, ROW, COL);int win = 0;while (win<ROW*COL-numlei){int x, y;scanf("%d %d", &x, &y);if (x >= 1 && y >= 1 && x <= ROW && y <= COL){if (inside[x][y] == '1'){printf("你被炸了\n");print(inside, ROW, COL);break;}else{int c = board(inside, x, y);show[x][y] = c + '0';print(show, ROW, COL);win++;}}elseprintf("输入坐标错误，请重新输入\n");}if (win == ROW * COL - numlei){printf("排雷成功\n");print(inside, ROW, COL);}break;case 0:printf("退出游戏\n");break;default:printf("重新输入\n");break;}} while (input);
}int main()
{   srand((unsigned) time(NULL));game();return 0;
}