【python写个可以运行的2048小游戏】

写一个完整的2048小游戏在Python中是一个相对复杂的任务，因为它涉及到用户界面、事件处理、游戏逻辑等多个方面。为了简化这个过程，我们可以使用Python的图形库，比如pygame。下面是一个简单的2048游戏的实现。

首先，确保你已经安装了pygame库。如果没有安装，可以使用以下命令安装：

pip install pygame

然后，你可以使用以下代码来创建一个简单的2048游戏：

import pygame
import random
import sys# 初始化pygame
pygame.init()# 常量定义
TILE_SIZE = 60
GRID_SIZE = 4
WINDOW_SIZE = GRID_SIZE * TILE_SIZE
FPS = 15
FONT_SIZE = 30
BG_COLOR = (235, 235, 235)
TILE_COLORS = [(255, 255, 255, 0), (238, 228, 218), (237, 224, 200), (242, 177, 121),(245, 149, 99), (246, 124, 95), (246, 94, 59), (237, 207, 114),(237, 201, 81), (234, 153, 81), (226, 112, 61), (235, 69, 69),(189, 54, 51)]# 初始化游戏板
def initialize_grid():grid = [[0] * GRID_SIZE for _ in range(GRID_SIZE)]add_new_tile()add_new_tile()return grid# 添加新瓦片
def add_new_tile():empty_cells = [(i, j) for i in range(GRID_SIZE) for j in range(GRID_SIZE) if grid[i][j] == 0]if empty_cells:i, j = random.choice(empty_cells)grid[i][j] = 4 if random.random() < 0.9 else 2# 合并瓦片
def merge_tiles(grid):merged = Falsefor i in range(GRID_SIZE):new_row = []for j in range(GRID_SIZE):if j < GRID_SIZE - 1 and grid[i][j] == grid[i][j + 1] and grid[i][j] != 0:new_row.append(grid[i][j] * 2)grid[i][j + 1] = 0merged = Trueelse:new_row.append(grid[i][j])while len(new_row) < GRID_SIZE:new_row.append(0)grid[i] = new_rowreturn merged# 滑动瓦片（向左）
def slide_left(grid):for i in range(GRID_SIZE):new_row = [val for val in grid[i] if val != 0]while len(new_row) < GRID_SIZE:new_row.append(0)grid[i] = new_rowreturn True# 游戏主逻辑
def main_logic(grid):merged = False# 向左滑动if slide_left(grid):merged = merge_tiles(grid) or merged# 向下滑动（通过转置矩阵）grid_T = list(zip(*grid))if slide_left(grid_T):merged = merge_tiles(list(zip(*grid_T))) or mergedgrid = list(zip(*grid_T))# 向右滑动（通过翻转矩阵然后向左滑动）grid_reversed = [row[::-1] for row in grid]if slide_left(grid_reversed):merged = merge_tiles(list(map(list, zip(*grid_reversed[::-1])))) or mergedgrid = [row[::-1] for row in list(zip(*grid_reversed[::-1]))]# 向上滑动（通过转置、翻转、再向左滑动）grid_T_reversed = [row[::-1] for row in grid_T]if slide_left(grid_T_reversed):merged = merge_tiles(list(zip(*grid_T_reversed[::-1]))) or mergedgrid_T = list(zip(*grid_T_reversed[::-1]))grid = list(zip(*grid_T))if merged:add_new_tile()return grid# 绘制游戏板
def draw_grid(screen, grid):for i in range(GRID_SIZE):for j in range(GRID_SIZE):value = grid[i][j]color = TILE_COLORS[value] if value > 0 else (255, 255, 255, 0)pygame.draw.rect(screen, color, (j * TILE_SIZE, i * TILE_SIZE, TILE_SIZE, TILE_SIZE))if value > 0:font = pygame.font.Font(None, FONT_SIZE)text = font.render(str(value), True, (0, 0, 0))text_rect = text.get_rect(center=(j * TILE_SIZE + TILE_SIZE // 2, i * TILE_SIZE + TILE_SIZE // 2))screen.blit(text, text_rect)# 主游戏循环
def main():screen = pygame.display.set_mode((WINDOW_SIZE, WINDOW_SIZE))pygame.display.set_caption('2048')clock = pygame.time.Clock()grid = initialize_grid()while True:for event in pygame.event.get():if event.type == pygame.QUIT:pygame.quit()sys.exit()elif event.type == pygame.KEYDOWN:if event.key in (pygame.K_LEFT, pygame.K_a):grid = main_logic([row[::-1] for row in grid][::-1])elif event.key in (pygame.K_RIGHT, pygame.K_d):grid = main_logic(grid)elif event.key in (pygame.K_UP, pygame.K_w):grid = main_logic(list(zip(*grid))[::-1])elif event.key in (pygame.K_DOWN, pygame.K_s):grid = main_logic(list(zip(*grid)))screen.fill(BG_COLOR)draw_grid(screen, grid)pygame.display.flip()clock.tick(FPS)if __name__ == "__main__":main()

这个代码实现了一个基本的2048游戏，包括：

• 初始化游戏板并添加两个随机瓦片。
• 处理用户输入（方向键或WASD键）以滑动瓦片。
• 合并相同瓦片并生成新的瓦片。
• 使用pygame绘制游戏板和瓦片。

你可以运行这个代码，并使用方向键或WASD键来移动瓦片。希望这个示例能够帮助你理解如何实现2048游戏！