输入带空格的字符串，求单词个数

1. 输入带空格的字符串，求单词个数
   1. __ueooe_eui_sjje__ ---->3
   2. syue__jdjd____die_ ---->3
   3. shuue__dju__kk ---->3 

   4. #include <stdio.h>
      #include <string.h>// 自定义函数来判断字符是否为空白字符
      int isSpace(char c) {return c == ' ' || c == '\t' || c == '\n' || c == '\r';
      }// 计算字符串中单词的数量
      int countWords(const char* str) {int state = 0; // 0: 在单词外, 1: 在单词内int wordCount = 0;while (*str) {// 如果当前字符不是空白字符并且状态是“在单词外”if (!isSpace(*str) && state == 0) {state = 1; // 进入单词wordCount++; // 增加单词计数}// 如果当前字符是空白字符并且状态是“在单词内”else if (isSpace(*str) && state == 1) {state = 0; // 离开单词}str++;}return wordCount;
      }
      int main() {char a1[]="  ueooe eui sjje   ";char a2[]="syue  jdjd   die  ";char a3[]="shuue  dju  kk";size_t len1 = strlen(a1);size_t len2 = strlen(a2);size_t len3 = strlen(a3);// 计算单词个数int wordCount1 = countWords(a1);int wordCount2 = countWords(a2);int wordCount3 = countWords(a3);// 输出结果printf("a1单词个数是: %d\n", wordCount1);printf("a2单词个数是: %d\n", wordCount2);printf("a3单词个数是: %d\n", wordCount3);return 0;
      }