C#，数值计算——插值和外推，分段线性插值（Linear_interp）的计算方法与源程序

1 文本格式

using System;

namespace Legalsoft.Truffer
{
    /// <summary>
    /// 分段线性插值
    /// Piecewise linear interpolation object.
    /// Construct with x and y vectors, then call interp for interpolated values.
    /// </summary>
    public class Linear_interp : Base_interp
    {
        public Linear_interp(double[] xv, double[] yv) : base(xv, yv[0], 2)
        {
        }

        public override double rawinterp(int j, double x)
        {
            if (xx[j] == xx[j + 1])
            {
                return yy[j];
            }
            else
            {
                return yy[j] + ((x - xx[j]) / (xx[j + 1] - xx[j])) * (yy[j + 1] - yy[j]);
            }
        }
    }
}
 

2 代码格式

using System;namespace Legalsoft.Truffer
{/// <summary>/// 分段线性插值/// Piecewise linear interpolation object./// Construct with x and y vectors, then call interp for interpolated values./// </summary>public class Linear_interp : Base_interp{public Linear_interp(double[] xv, double[] yv) : base(xv, yv[0], 2){}public override double rawinterp(int j, double x){if (xx[j] == xx[j + 1]){return yy[j];}else{return yy[j] + ((x - xx[j]) / (xx[j + 1] - xx[j])) * (yy[j + 1] - yy[j]);}}}
}