C语言入门到精通之练习36：一个最优美的图案（在TC中实现）。

题目：一个最优美的图案（在TC中实现）。

程序分析：无。

程序源代码：

实例

//  Created by www.erdangjiade.com on 15/11/9.
//#include "graphics.h"
#include "math.h"
#include "dos.h"
#include "conio.h"
#include "stdlib.h"
#include "stdio.h"
#include "stdarg.h"
#define MAXPTS 15
#define PI 3.1415926
struct PTS {int x,y;
};
double AspectRatio=0.85;
void LineToDemo(void)
{struct viewporttype vp;struct PTS points[MAXPTS];int i, j, h, w, xcenter, ycenter;int radius, angle, step;double rads;printf(" MoveTo / LineTo Demonstration" );getviewsettings( &vp );h = vp.bottom - vp.top;w = vp.right - vp.left;xcenter = w / 2; /* Determine the center of circle */ycenter = h / 2;radius = (h - 30) / (AspectRatio * 2);step = 360 / MAXPTS; /* Determine # of increments */angle = 0; /* Begin at zero degrees */for( i=0 ; i<MAXPTS ; ++i ){ /* Determine circle intercepts */rads = (double)angle * PI / 180.0; /* Convert angle to radians */points[i].x = xcenter + (int)( cos(rads) * radius );points[i].y = ycenter - (int)( sin(rads) * radius * AspectRatio );angle += step; /* Move to next increment */}circle( xcenter, ycenter, radius ); /* Draw bounding circle */for( i=0 ; i<MAXPTS ; ++i ){ /* Draw the cords to the circle */for( j=i ; j<MAXPTS ; ++j ){ /* For each remaining intersect */moveto(points[i].x, points[i].y); /* Move to beginning of cord */lineto(points[j].x, points[j].y); /* Draw the cord */}}
}
int main()
{int driver,mode;driver=CGA;mode=CGAC0;initgraph(&driver,&mode,"");setcolor(3);setbkcolor(GREEN);LineToDemo();
}

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