Swift对比版本号

在 Swift 中比较两个版本号的大小可以使用以下方法:

func compareVersions(_ version1: String, _ version2: String) -> ComparisonResult {let v1Components = version1.components(separatedBy: ".")let v2Components = version2.components(separatedBy: ".")let maxLength = max(v1Components.count, v2Components.count)for i in 0..<maxLength {let v1Component = i < v1Components.count ? v1Components[i] : "0"let v2Component = i < v2Components.count ? v2Components[i] : "0"if let v1Value = Int(v1Component), let v2Value = Int(v2Component) {if v1Value < v2Value {return .orderedAscending} else if v1Value > v2Value {return .orderedDescending}}}return .orderedSame
}

使用示例：

let version1 = "1.2.3"
let version2 = "1.12.1"
let result = compareVersions(version1, version2)if result == .orderedAscending {print("\(version1) < \(version2)")
} else if result == .orderedDescending {print("\(version1) > \(version2)")
} else {print("\(version1) = \(version2)")
}

输出:

1.2.3 < 1.12.1

此方法将版本号按照 "." 分割成各个组件，然后从左到右逐个比较每个组件的大小。如果某个组件的值小于另一个的值，则返回 .orderedAscending，如果大于则返回 .orderedDescending，相等则返回 .orderedSame。