[leetcode]squares-of-a-sorted-array. 有序数组的平方

. - 力扣（LeetCode）

class Solution {
public:vector<int> sortedSquares(vector<int>& nums) {int n = nums.size();vector<int> ans(n);for (int i = 0, j = n - 1, pos = n - 1; i <= j;) {if (nums[i] * nums[i] > nums[j] * nums[j]) {ans[pos] = nums[i] * nums[i];++i;}else {ans[pos] = nums[j] * nums[j];--j;}--pos;}return ans;}
};