rust语言match模式匹配涉及转移所有权Error Case

struct S{data:String,
}//注意：因为String默认是移动语义，从而决定结构体S也是移动语义，可采用(1)或(2)两种方法解决编译错误；关键思路：放弃获取结构体S的字段data的所有权，改为借用。fn process(s_ref:&S){//&S ，借用match *s_ref { //S ， 值//(1) match s_ref { //&S ， 借用//(2) S{ref data} => { //data:&String ， 借用S{data} => { //出错点.println!("Data: {}",data);},// _ => {},}
}fn main(){let s = S{data:String::from("hello world"),};process(&s);
}

编译错误：

   Compiling playground v0.0.1 (/playground)
error[E0507]: cannot move out of `s_ref.data` which is behind a shared reference--> src/main.rs:7:11|
7  |     match *s_ref { |           ^^^^^^
...
11 |         S{data} => {|           ----|           ||           data moved here|           move occurs because `data` has type `String`, which does not implement the `Copy` trait|
help: consider removing the dereference here|
7  -     match *s_ref { 
7  +     match s_ref { |For more information about this error, try `rustc --explain E0507`.
error: could not compile `playground` (bin "playground") due to 1 previous error

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