力扣108. 将有序数组转换为二叉搜索树

108. 将有序数组转换为二叉搜索树 - 力扣（LeetCode）

找割点，一步一步将原数组分开。妙极了！！！！！

/*** Definition for a binary tree node.* public class TreeNode {*     int val;*     TreeNode left;*     TreeNode right;*     TreeNode() {}*     TreeNode(int val) { this.val = val; }*     TreeNode(int val, TreeNode left, TreeNode right) {*         this.val = val;*         this.left = left;*         this.right = right;*     }* }*/
class Solution {public TreeNode sortedArrayToBST(int[] nums) {if(nums.length == 0) return null;int mid = nums.length/2;TreeNode t = new TreeNode(nums[mid]);t.left = sortedArrayToBST(Arrays.copyOfRange(nums,0,mid));t.right =sortedArrayToBST(Arrays.copyOfRange(nums,mid+1,nums.length));return t;}
}