easy-es Map类型字段序列化问题：Unexpected character (‘n‘ (code 110)):

@Data
@IndexName("demo")
public class EasyEsDemo {@IndexIdprivate String id;private String name;private int age;// 这个Map字段因为NameFilter过滤器，导致fastjson序列化后为{null:"value"}这种形式，insert报错private Map<String, Object> data;
}

上面Map类型字段保存报错如下：

Caused by: ElasticsearchException[Elasticsearch exception [type=json_parse_exception, reason=Unexpected character ('n' (code 110)): was expecting double-quote to start field name
.....

此错误主要原因是：EntityInfoHelper中创建的NameFilter是一个匿名类，看上去主要功能就是过滤排除字段，但是针对Map类型字段就出现了问题，导致序列化时候Map的key字段变成了个null. 导致fastjson序列化后为{null:"value"}这种形式，insert报错。

EntityInfoHelper中NameFilter过滤器代码如下：这个过滤器导致序列化Map类型字段时，获取的key当成类的字段属性处理，而类中没有名字为key的字段，所以过滤器过滤完后key变成了null

    /*** 添加fastjson字段过滤器** @param entityInfo 实体信息*/private static void addNameFilter(EntityInfo entityInfo, List<SerializeFilter> preFilters) {Map<String, String> mappingColumnMap = entityInfo.getMappingColumnMap();Map<Class<?>, Map<String, String>> nestedClassMappingColumnMap = entityInfo.getNestedClassMappingColumnMap();if (!mappingColumnMap.isEmpty()) {NameFilter nameFilter = (object, name, value) -> {Map<String, String> nestedMappingColumnMap = nestedClassMappingColumnMap.get(object.getClass());if (Objects.nonNull(nestedMappingColumnMap)) {String nestedMappingColumn = nestedMappingColumnMap.get(name);if (Objects.equals(nestedMappingColumn, name)) {return name;} else {return nestedMappingColumn;}}String mappingColumn = mappingColumnMap.get(name);if (Objects.equals(mappingColumn, name)) {return name;}return mappingColumn;};preFilters.add(nameFilter);}}

不知道是个bug还是不推荐使用Map类型字段。或者说有别的处理方式。目前使用的处理方式如下：自定义一个Map的序列化器，并在Map类型字段增加注解

public static class MyMapSerializer extends MapSerializer {@Overrideprotected String processKey(JSONSerializer jsonBeanDeser, Object object, String key, Object propertyValue) {// 删除了 jsonBeanDeser.nameFilters 的处理逻辑if (this.nameFilters != null) {for (NameFilter nameFilter : this.nameFilters) {key = nameFilter.process(object, key, propertyValue);}}return key;}}// 手动指定自定义的序列化处理器@JSONField(serializeUsing = MyMapSerializer.class)private Map<String, Object> data;