React antd umi 监听当前页面离开，在菜单栏提示操作

需求是我这里有个页面，离开当前页面之后，需要在菜单栏显示个提示，也就是Tour

const [unblock, setUnblock] = useState<() => void>(() => () => {});const [next, setNext] = useState('');useEffect(() => {const unblockHandler = history.block(({ action, location }) => {if (action === 'PUSH' || action === 'REPLACE') {setNext(location.pathname);setLogoTourOpen(true);return false;}});setUnblock(() => unblockHandler);return () => {unblockHandler();};}, [history]);const handleTourClose = () => {setLogoTourOpen(false);unblock?.();if (next) {history.push(next);}};const [refs1, setRefs1] = useState<(Element | null)[]>([]);const [openLogoTour, setLogoTourOpen] = useState<boolean>(false);const steps2: TourProps['steps'] = [{title: '',description: `You can click on the logo to easily logo back to the Get Started page `,target: () => refs1[0],placement: 'bottom',nextButtonProps: {children: <span>OK, I know</span>,},},];

// 放在组件里就行<Touropen={openLogoTour}onClose={() => {setLogoTourOpen(false);updateGettingStartedInfo('logoPage');handleTourClose();}}steps={steps2}/>