#力扣：771. 宝石与石头@FDDLC

771. 宝石与石头 - 力扣（LeetCode）

一、Java

class Solution {public int numJewelsInStones(String jewels, String stones) {int[] isJewel = new int['z' + 1];for (int i = jewels.length() - 1; i >= 0; i--) isJewel[jewels.charAt(i)] = 1;int cnt = 0;for (int i = stones.length() - 1; i >= 0; i--) cnt += isJewel[stones.charAt(i)];return cnt;}
}