【JAVA springframework.http】如何发送HTTP请求

Springboot之restTemplate

• https://blog.csdn.net/weixin_43702146/article/details/116567707

public Result doHandlePostJson(String restUri, String jsonData)throws Exception {Result result = null;try {// logger记录log.info("doHandlePostJson request restUri:" + restUri+ " sendData:" + jsonData);HttpHeaders headers = new HttpHeaders();headers.setContentType(MediaType.APPLICATION_JSON);HttpEntity request = new HttpEntity(jsonData, headers);// 发送http服务请求ResponseEntity<String> response = restTemplate.postForEntity(restUri, request, String.class);// 判断返回结果if (response.getStatusCode() == HttpStatus.OK) {// logger记录log.debug("doHandlePostJson restUri response success,interfaceUri:"+ restUri);// 获得返回结果String repData = response.getBody();// logger记录log.info("doHandlePostJson restUri response success,return data:"+ repData);// 返回成功result = Result.succeed(repData, "");} else {// logger记录log.info("doHandlePostJson restUri response error,interfaceUri:"+ restUri + " http status:" + response.getStatusCode());// 返回产品Gateway通讯异常错误result = Result.failed("请求外部系统异常");}} catch (ResourceAccessException e) {// logger记录log.error("doHandlePostJson restUri ResourceAccessException:", e);// 返回通讯异常错误result = Result.failed("请求外部系统超时");} catch (Exception e) {// logger记录log.error("doHandlePostJson restUri Exception:", e);// 返回通讯异常错误result = Result.failed("请求外部系统未知异常");} finally {// 关闭}return result;}

package org.springframework.http;

HttpHeaders

public class HttpHeaders implements MultiValueMap<String, String>, Serializable

HttpEntity

public class HttpEntity

HttpStatus

public enum HttpStatus