输入一串字符串，前中后都有*号，去掉字符串中间和后面的*号，保留前面的*号和字母

#include <stdio.h>
void  fun(char* a)
{//***df**fr*fg***int i = 0, j = 0,n=0,m=0;char* p;p = a;while (p[i] != '\0'){i++;//i是一共的字符的个数}printf("%d\n",i);while (a[n] == '*'){n++;//计算字母前的*的个数}printf("%d\n", n);m = n;for (j = n; j < i; j++){if (p[j] != '*')a[m++] = p[j];}a[m] = '\0';
}void main(){char  s[81]; printf("Enter a string:\n"); gets(s);fun(s);printf("The string after deleted:\n"); puts(s);
}

输出的结果：