HJ73 计算日期到天数转换

HJ73 计算日期到天数转换

int main()
{int year, month, day;cin >> year >> month >> day;int monthDays[13] = { 0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334, 365 };int nday = monthDays[month - 1] + day;if (month > 2 &&((year % 4 == 0 && year % 100 != 0) || year % 400 == 0)){nday += 1;}cout << nday << endl; return 0;
}